EECE 210 Homework, Spring 2008
American University of Beirut · Electric Circuits · 5 pages
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Homework 8
Solution
15
P83 [a] in(0) = 300 = 75mA
ip(0) = —45mA
ic(0) = ~i,(0) - in(0) = 45 — 75 = —30mA
b) a= 555 . = 12,500
(b] °= 2RG = 2000210)”
we : : = 108
= IC (50 x 10-)(0.2 x 10-*)
$1.2 = —12,500 + V1.5625 x 108 — 108 = —12,500 + 7500
51 = —5000 rad/s; 8p = 420,000 rad/s
vy = Aye 500 4. Ao @7 20,0008
v(0) = A; + Ag = 15
du —30 x 1073 4
aO = —5000A; — 20,000A, = Dax = —15 x 10°V/s
Ne
Solving, A,;=10; A, =5
V = 10¢e7 500 4. Fe 20,0008 Wy t>0
. du
[c] tc Ca
= 0.2 x 107®[—-50,000¢®0% — 100,000e~20.0004}
= —10e75000F _ 99¢—20,0008 mA
ig = 50e °° 4 25 e770 mA
i, = -ic — tp = 4000 — Fe mA, t>0
1
P810 [a] a= 55 = 0.5 rads
> 1
we = 7g = 25.25
wa = 125.25 — (0.5)? = 5 rad/s
v = Bye? cos 5t + Bye~*/? sin 5t
v(0) = B, = 0; v = Boe~/? sin 5t
ig(0t)=0A; — ig(0t) = 4A; S(O") = pag = 50Vi5
dt
50 = —aB, + wgBo = —0.5(0) + 5Bo
Bz = 10
v = 10e~*/? sin 5t V, t>0
[b] “ = —5e'/? sin 5t + 10e7“/?(5 cos 5t)
#0 when 10cosSt=sin5¢ or tanSt=10
Bt; = 147, t, = 294.23ms
5ta=147+7, t2 = 922.54ms
5tg=147+2m, ts = 1550.86 ms
2
fe] ty —t, =1256.6ms; Ty = 2 = 2 = 1256.6 ms
Wa 5
T, 1256.6
[d] t2 — t; = 628.3 ms; z = > = 628.3ms
[e] v(t:) = 10e~©14") sin 5(0.29423) = 8.59 V
u(t) = 10e~ 4?) sin 5(0.92254) = —6.27V
v(ts) = 10e~ 774) sin 5(1.55086) = 4.58 V
10> v™)
P 8.29
1 1
®= ORC = 2(400)(1.25 x 10-8) ~ 10
2 1 _ 1 _ 4
“o= TG = 25x 10-105) * 10
81,2 = —1000 + 1000? — 64 x 104 = —1000 + 600 rad/s
8, = —400 rad/s; 82 = —1600 rad/s
UVo(0o) = 0 = Vz
"Up = Ale 40% + Abe 1600
vo(0) = 12 = A, + Ay
Note: ic(0t) =0
dv,
(0) = 0 = —400A/ — 16004}
dt
Solving, Ai = 16V, AL=-4V
Vo(t) = 16e~ 4 — 4e7 160% y, t>0
P8.42 [a] t <0:
io = - =100mA; v9 = 500i, = (500)(0.01) = 50V
t>0:
R 50 _..
“= 97 = 3a5xioy 0 TS
1 1
2 = = 108
“= TG = Exitos Goxioy ox"?
a=we .. critically damped
". ig(t) = Dytet + Dye 10"
i,(0) = D2 = 100mA
di
a) =-aD,+D,=0
D, = 10°(100 x 107°) = 10,000
io(t) = 10,000te 2 + O0.1e7A, *¢>0
[b] vo(t) = Dste“!"* + Dae"
Vo(0) = Ds = 50
dv,
C=, (0) =-0.1
du, -0.1
FH = x07 = 775 * 10° V/s = —aDy + D3
Ds = 10°(50) — 25 x 10° = 25 x 10°
Uo(t) = 25 x 10°te 1 + 50e VV, t>0