EECE 380 Exam 1 Solution, Fall 2011

American University of Beirut · Engineering Electromagnetics · 6 pages · with solution

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EECE 380 Exam 1 Solution, Fall 2011, page 1

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Exam Scuton Cui f. »P coblam 4: ex€- Ac ay ag =Cé60~6) a, +(3-Bo)ay + Elo -lo)ag a ‘e 3. = (66,-24,-70) \ExFl-J6e* 2a", 26" 2 44.06 © is We cat choice Pralolomn <3 Mie stant choi ge Ae Pcelolum 4 a (D os Wo Talk choi te Rcololum 5 Sports ec by | | ce \ 4 Up \ ( Xe X ‘ \ oa 3y “ uS Ler) 1 Nac coy Ba, TSUN D Oey a meee whem path L has laren divided dake Seamemts objbc,cd and da as Shown Ur the Fqce » Mong ab ,cai2 awk dQ-rdGa@® home use b i Ado -J rs Grp = 2 Ces) | -2( dea -1L) = -JST4l o a G $=60 Mona oc , Gh = BOP 45” amd AL- ara, - Were c S Vaca = J rees@de = cos us b L a2 2 rae ra aL - U2T« 2 * Mong ad, C= 5° onal dhavddag , 4 d 6° Coe Sade =f cso BSE 2S Cesg)| = 5 ( 4 -%2) c . a ra P=45° 45 = ~SC-S7) 7 —___ 7a - Wor da, Dp - 60° ond dL2~Aca, . Hence S Rds Cc cesgde = cose | =a + 2l 5 q a C25 Pudiina, all Vege. \ogether cede WA A.dQ=-J24l 4 use _ 5-55 at L 4 a Y = ~t0n 4 ,2Ou _~o-19 ST oat = @Fou —t* 4S G q <<) 4 = 2.4935 scan, Steers theorem Checomae L na desea eth) Gaal. Tovah) ds Buk 46. cd¢de a antl aA afr _ Ae t fd (cay) aft 7x Nea, {+ Bas - Be] oe (She ed ee S-(cAy) ag = Co -0) A + (o~o) ge 4 4s Cirr)eagmag Reo blow A RQ BenC wor (o,0) Y= 3 cartes (on C/m™s & fad Doak Co,4,3) ak (oi4)3) dua te MR -BSL ey Wi - GAG = § E = Roxio" (3g + Har, J go 4 t — * Ber <'o° 25 D+ Se E. Boris? C2e, +t) UT «128 eT) duahe S, ; C= Bs & = lox ©" a ; * : : | 22, + Ze % = 2, Gs t& = Sey un 9} w x c Dr-D, +B = WEE +¥e Sy, Say = 0.0892 S, 4 5. oPETY NS 2 MTX AZS ™ QD we cig choice . Yrollem B 5 Quite NC /_? Ce at v=2; €= 9 wn a oe T rg ned! . Ses .¢ “SR Ode die = fs j"fatacs Gt Ste ede fie = retC it) iv coal) = ae eye Mectde (suede (ax lo © ° = = ("cu wen Vane ExY=h [ww jE. 'c- eo 4 9 é. X™ ly et « ? wt AT = § Zcrdc “5% (sine fie bo o = 2.10" tee | F 2sidt actu Se hence c. ‘he lot uct? _ Es ctxto" _ _o fe a> son *'S 2,63 4 —_ = = 26. ay Vim. saggy = CREA [wn ®© a te igh Avie - Recelom 4 % VYexr4¥eky rte Fat C14r3)7? Ee VV =o] Cegia + Cmte) EAR] Ear CUu2%sye- (3&2, +Oay +2O) = -Bay- tay Ox» ho riawct choita. Problem (© x Sie Qe normal) fo the bowrdary plane, we ehtaue lity nor nial Comenrenty, ar: Ey= Fy @= Si A, =3 E,,: 3 ne Saws CE, ary Oe a2o E. E,+Ee eres, EF.. += &,- Gy, = 3a. ~ Cay Rivets Cle Ee = ke ~ %ay Similonla, DL, = DBD, hn —> — | cr Ce, -€ ron Ein elas ec &, -2(2@,) = ay Ce Wr Fe = Cre t Ean 2 SQL -2Ty tO By K Wn Mw te NA choia —) Bay ~2aly [= = Sax ~ Cay +aarx Redduuw WV \ BCHHi15) & UW Neo Areleckrre medium sce Y=ldp at B = = 36 a = Nie 56.54 Y iw) SKlO x lO ~ iZTa = Ey fim aural E- - A q TH we Tar doi ce. PR rolbowr Vay Se CRY)= aidR Py C)y=az0 2 Cr)= Testo ara b=§ S$, CRy= SR CCl) Des = RE C Clim) > = Q Os RE Re CC/m™) ® atu cight cosa