MATH 202 Exam 2 with Solution, Spring 2006
American University of Beirut · Differential Equations · 7 pages · Prof. Kamal Makdisi · with solution
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Math 202 Que Seo om QH0S- oF
Sec ons \- 4 (Prfesser Komal Chori - Maka: x)
1. (16 points; please try to solve on this page and the nexi one) Find the general solution of the
differential equation
1
eo
Hint: part of this problem needs variation of parameters. You are allowed to write down the system
of equations involving wu; and ug directly, without deriving them. For the integrations, J suggest,
using the substitution w = e* and some partial fractions.
y” + by’ tayo dt sinde + S
Yo: cvs any 4s m4 Suet wely 1,74 - Ae™ Hye
Me= +
(os Xmre eo e
Deedee Sey whee L Gap f= x3 Lye: 2-2 \ Greg) =
er |
Up |: LOIxj= Sethe L (An @]< A (64.9 = (ShA4BD 4 HAs Rata xe
fh. LO V= 4 +64)
LELw\s 4 a
\nee | L 3 x Va Mac
( “* - B wh . % — li ia hker Noter
4 Reyes yxe Sk, ‘
Sey Lfet}- -iont 5 Lf-s ests | ee \ Yt vos Dm
( LCs Yo\ = \vew x) nn
ceed 4 ‘
: wh = 4, rd. qe ) wean PH Tee
J Pe Se re ye fort fay uy ge (DE ig trod)
x | Hy tg 1D) ome oy aerating
(eo eu Fre “wy = ~ fen Yeo | .
x, “yg Le
-ey, -He “o) < a @ “36 “rg GO => 4, r =
$Q =3 o/s ab a
ex a dua e” |
7
es
&
F
%
iw
2. (16 points; please try to solve on this page and the next one) Using a series centered at x = 0,
find the general solution of
y" ~ 3ay'—y =0
Meo ke on ordin + so Mek c = “ ' oe Ret w_ °2 aD
e af ax < fn = EB efenagx eS
(pee Os ; nro , 4 Aro ax | 1 hzo 2m
S 1 & 4 =
a-
DE Lecemes. 2 n(a-D eo, x + 26-Dn CO, + en) c,x” =o
‘ oe eed zo
ne
combine
= n ad
o 2 nln t) tn _ j (Bn41 en x2 oO
mo nto [eek cue (*) See lela,
\~ ten «< dees koh
= kCe-1y ce xe ~ 2. BbDe 7 rt 2 Oo
Ne
feve = h Bx -5)
Seve sine POUT eA CE
kro = Ocgre fone me k22 => Me-da,~Gk-s)o,, =O
lez) =p O20 sy cee
a Be < Cer | CRderm reunmeree)
L a oem
aN names GS 2-5
Ce C. AT Cu oo~ Oe. (8-1)
Ce 0 Oy Ceegy en:
\ ros a
Cyc he a ob 2 DA
T D cy a, Co, Ce ae b, Cx
oS e 3 oe
a2 eu a Ss
Cy Coes ims oa" AD
2 is ‘S$ = ¢,
Cees {k: 5) Ce 7) 4 al Creag”
& Y.lo i $ |
Sa RE, SEP A, cae Holt _ tole. (69-2) TT By-2z) |
. : ae tare ! Capa = (anys %y = jet Ze,
Pe ’ (WI) i
a .
on }- Gt cee cyte egyie = = ali+ abe Wah DIB em
= ai 7 "
OK + cau +e gx? + 9x?» oe ca) ‘ + re. ten mS
TH ta,
HB Miho VS ato 169 10 te AG 4H
Oy] t HKG Ke DE ey a Plot 1b 9
ne a! ayn" 8, a * xt) x,
ad Ile >) an g (é 2) o., | bot J
T,]- 5) 28 Hy, yD ater
\" ob ental eee So eee x + qe JEL
\ Qzo CH | fo CD
L = nates
a , lie obit the bet Ricoh He Ded gek ae
Rema v on & ‘ $ G A L Set show ee,
S (eerteedo, x — kaqx to =) aes
x a ate kep Be recurrence Ca = (eaten ryt {, k20
ted 3
Ch ance Ws leads tae coun Ahn)
3. (16 points; please try to solve on this page and the next one) Using a series centered at 2 = 0,
find the genera] solution of
Qa? y” - (a? — Bx)y! + 3y = 0.
were xe
ee Pe Seer 2 Se ea 3 xXco is epvlen singer b,
Dy ,* ’ R ae Xx x ° p
x oe den Shin dew
nar 2
natot ue (owe ry
J YE EGO Denn
Neb
We Use. 4°
s nee LE aden &
i. an aan En
hee =o
t | . a aot ~ I _
Subrchvee in 22¢ i “bxy +3y <d
of nett OA nee aw
ec, > aimee Dee 4 Bo Cneed a 4 Salmo)ar Stax"
Reo are Are
heb co
Li _ —
Tad be , ere Scr teh & £ q:
serps oe. ae > CO OEO nx 20 iF Ucate we haw o Coe
° 3Yrrr-) Ge + :
Qde (aoe AN h~o ayiek htt) Quiy-l-2us B
ned ok ne Fo) 7 > Qe -Su43
{ Ce en) | seser ke! =(0- 30-1)
ray em kar
kar a x =O
a. (2to-3Leer) qe E Chew Dy,
keo : ket
PE Corner e _ eee mae —
Wee -d : — - a _
Set boo 5 (2r-3te Me . kel oy C2 - Sere, s Cer" De, ~ °
a iT to 4 \ rsh ow ce! | a es
BH ete nla et) whe Hay bat “pd kate ite 20
rede fet OA
Cre ee woe Ber hy Yrle gL NT om
NGL, fe We wil afk Q shes nities)
So are) fo Rive am coral HL. pawns Ee ont
oN cancal ik Maher tasheed :
Peweves, Lu
: nwa oie. o ke
As osWvh) re % | emurren me Sy (206 %)-3) (4) ge (KER -D Ca Be \
\ be Fales kal te
cm AEG + CREO be Ata
~ adel
o cnc wy here y
woes Bek Mga th gg |e bay
‘ Be -|
dt aa Hae Pre
= a a
Cc, he —s__, yn. m— Ge," ch
> Ged? Sr Gay Ceay 3 Seng 3
3, 1A yy
i <)
1 \
Robe. we om, rwahe 4,= % a 5¢ G1
20 ‘
3 — continued.
he selolan | Tel recorrence Sens (end syCeu Ne, Ckat-0) c <0 Rh ke
2 |
& Lede Key 20 Rekzi seber oth on be emceled
SS
\Cy ~— wer
_ 2e-\
| . t
c t 4 % Be
° Cc — ie
Ck) ' fhe “ ae) _:- Ce Ch
‘4 (k= 3) ‘ees
\
“lo ~ te . 7! ne
ci Te 3 pase, Ct ie?’ - aoe c,
13-5 eT
sale, Mae cov ac, sept a pete _ ie Co (arse check Yast
“Foy ae Gaol
“ef, Git
roan 1 ZaHl l eae @
am Km Ue . -t
a Bee em
oa] 135. - (ey
No Y
CD Qri
Se ao % 2. : .
4 - Qa!
Qro .
_
-SowwTen 4 = Ay, + By
ee a 3 do \ |
- LARC Coe Rey |
- i = a x +R tam —- %* :
| Q=o 2h Qeo 2R)'
Le — J
4. (8 points) Using any method that you like, find the genera] solution of
ba*y” + 82y'! +y = 0.
Tha see Covey Ber equchen,
a . Sam ye x, oe atk
oie ® loki A thy i) ‘ a
Ser -1) Xx Ne rex 2 © te es onlin ate.
> FC -Uviee & re s1Eee L Vann
salobens \
= omen
ers 5 tek -
we here conplee Sohn : os 1( 3, ig L
Es) na ag S 4 gu x (e > x FC es (kid + ‘4 (% nx)
Ye * * Ss eek = «8 (alex) = (9)
[ ws wall make a shhh xee= — Cdetails WPL a p>)
‘ .
4g 5-2 = p43 ogre Cs emt uxt “ Ink now ante elt)
‘755
wth rocks Me Mat 142. oe ouxiliny nh
5
= ashe alto + Bea (%t)
Nn (Kd Red mm (%lax)
7
5. (8 points)
a) Use the Wronskian determinant to show that the functions ¥, = 2, yz = cosx, and ys = sins
are linearly independent.
; 4s 13 5 :
WG oy — pede (TY a ; ; . let ( * ete Smee
> 13 Lh ashe Cex
" uM ”
rn
10> Os Sia oe
ten
© > pond ale Ick column Cong othe Clece
= x ke fo RT™ Cox fULX Ga x wares jor well, ba Mus ig
—\. ‘ \ Lo ( easier )
- ree . deg
- dlos'b are)
= KX. [+5 x ~(-o8 "| - [sp
[a x
e
Ut -Slaw ,
roMK Coby certs) =x,
; WC ar a
See OG, ty ot dekely wee we Gabel oy Onl ya om beer
eee Oo cad oder bengentee nae BE ole |
yourl ale ig zhx
b) WITHOUT using the Wronskian determinant, show directly from the definition that the *he-®
functions y) = 1, yo = e*, and yg = e7* are linearly independent. Coie
ere we amie hws ‘her Tha oe ® A+ &e% + Ce~* = 0 f, all x
hos One or Ve Arwsl glubn owe ABC are al\ zero,
Vor metal, ee OD I Lekvahee $9 ; ae 4 dhe,
‘U) A+ Ge%Q Ce" =
ee ne
@ RE- Ce% Oa go six } These esta => =
= / we kee
*.ce%<e woo
a>) be € mil Ey vad est) ae
BYMd vk nel &
=> h=@-Cee Con. vee Ker), G fay siete A ® mwa be the diye! On
Az heCro
BQ 1,e%, Om ae Wreerdy rhage,
for de
—— wt xe!
Dd mative a eve Graton ela Seppe A nee, BL,
A *+BrC =o @ (49881 coy - Aa Rr =o ©
9% A x Re +Gr0 (>) (fp caee KEL) a) - *C(k 4) =0 (Hw “oe)
oe, a +Cero@ Chew xe-1) (1) +e) a @ -e/
ey
Fe \) +B+C 2 § oe oS Reo
=F t- fre “Eom Car beens ye kso 2S ote
“exc re Aeinceo we rete Cab Tah ES
6. (8 points) Consider but DO NOT SOLVE the differential equation
w?(a — 4)? (2? — da + 5)y"” + (2 ~1)(e@— Ay’ +y =O.
Repeat: DO NOT SOLVE THIS EQUATION!
8) Identify the singular points (both real and complex) and indicate which singular points are
regular singular points.
pe SD) 2 Oe To onake Hee the no of
7 Cl HAY CEA +8) x(x 4) 63 Hy +5) e-4¥+ 5 Ae Dal, by
| Shy peels IE ae Mle,
R . Bat OOHars) 5 ee Can feck Row oS 2 &-OCx- PD
* uM, f= 241 Be 2-1
O Me soul fee one Muse lene oth Per Q ha ao
sda of he dare nabers of the one, The Smt
te nie Super gees one. Aha supe Penta Keg gech the the dons ai netye me) P
conte as ob musk the Lick (x a) be Hee densi noter & Q Contes GL math the
aur. facta Geay*,
Cte eth aqomrt. So
fe rellen Soper pot oe welt) neeei, node |
b) WITHOUT SOLVING THE DIFFERENTIAL EQUATION, find the minimum guaranteed
The ony Weeve rere see PR bee x pee Ke the denon rah,
radius of convergence of a series solution of the form y = S p(x — 3)". Justify your reasoning.
n=0
[Lok at- the conter x=
Qo the Fogle powks ©Ae x20 xed yee) ” The, Complex place:
cal @® 7 Me & dences Le 2 earch,
sinter pon One. Orcled
Ree Ley, <2 rw
By Ate Theeren, we ane evirmlee$! a alin Guanteed tedis ot Conve
ale. _
(© Cur sewhun Sc, lx on
1s Guaranteed 4+. Cenvere Lf. |x-2\ <i »
9