MAT 113 Exam 1 with Solution, Fall 2007
Notre Dame University–Louaize · Intensive Calculus · 7 pages · with solution
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x? —4x4+4
x? 45x? -14x
1-(10 points) Find the following limits: Q) 4 lL, nae C
a) lim, ,.
—
x-2
-4
(Giver reasons for your answers)
Cone c >) Coy u wafiteed = Cho vs discad hye 2.
2-(10 points) Can f(x) = be extended to be continuous at x=2 or x= -2?
GS
K-52 ° a> 2 Cx 2x42) XY KxD q
& Roo Can \e oxtoncleL he be cud A W225
aad OF extend Poahan ke Foye fF Ka? § x42
=
5 K-22.
«Gey - — gl a : \
zn ( 5 =) BEB u “Bele ined =» ¢ (x) dinate xa
rf. OZ ay 8 a) Agen net emg
X game 2
‘ - WT Ce “wK i ¢ xb uA p (x) h ke Cah Cond, am
3-10 points) Show that f(x) =x? —2x +2 has a root between -2
ay iG C oy
Tee wi x+. 2 .
cs Cos « x3 2 M2 F cond ba lo2te
) \
(aud Colas oF ann = Gem
FO =e 256
- oe +. leer he vols jee pr pee e € C © i.
0 Here bo aheet a € (- 2,0) Such Pat (0 oc) = °
4-(15 points) Find the derivatives of the following functions:
2 = (. 9 2. --| > i (2 4: , i
a) f() == 8? = + 3Xo- ax+t JX = x 3 X 2 2 47x
\ Hl ; 3 =a Wie 3 . 5
(x2= UV a bY -2vw Te UX eR L 2
5-(12 points) Use the definition to find the derivative for f(x) = 2x? +5,then find the
equation of the tangent line to the curve of f(x) at the point of abscissa
x=2.
A \
\" (Care — Rc K+ Wy oe -\ 2¢x x vey 4&5 _( 2xt £5)
= - ys. \
= 9) a x teahxalh) 4 +5_ 2x26
dy
| ; \ ATES
PC =k ene ee ea -
ZF vo ; _
a)
ohn ie 4h) 7 i Vx p27 OMX.
= _* ho
pt J bake opt pevlact - Calis. 17) = (2,13)
r= Sue of the trogiat Mp Pee) = 402) = g.
eq J Foe Tang ent May 13 28 (x-2)
J = 8X _\ 64\3
[o = 8x 3 | .
ints) Find the equation of the normal line to the curve x? —3xy + y’ =—1 at the
point (1, 1).
Sa
{a
4
y Dae fos ix qh , al bus Baar h Gi,1)
Ne
/ Sym). stone of The ae! Se “A Yul =) ele
oo menal coer.
7-(15 points) Find the slope for the line tangent to the curve x= 7 tant, ead at
2
4 Also, find the value of + at this point.
8-(13 points) for what values of m, if any, is f(x) = {
a) Continuous at x=0?
Ww,
ei
sin(2x), x<0
mx, x>0
b) Differentiable at x=0? [EE 5D
| 7,
re > a
=)
Qc o7) = _ ane = Sk
X— > 6-
DYE SOe= be— bon ag
Cee) = ae C5.
et)= 0 = Cees = Stn (ey