DCSN 205 Homework Solution Chapter 9, Fall 2015

American University of Beirut · Operations Management · 3 pages · with solution

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Solution Chapter 9 exercises (9.5,9.17) 9.5 Load  Distance A  B: 450  30 = 13,500 A  C: 550  60 = 33,000 A  D: 50  90 = 4,500 B  A: 350  30 = 10,500 B  C: 200  30 = 6,000 C  D: 750  30 = 22,50 0 90,000 Note: Work areas are “fixed” if using the software to reach this initial answer. (a) Initial layout: Interstation Distance Matrix—Original Layout Pick Up Pick Up Verification Paperwork Advising Class of Status and Forms Station Cards and Payment (A) (B) (C) (D) Paperwork/ Forms (A) 0 30 60 90 Advising (B) 30 0 30 60 Class Cards (C) 60 30 0 30 Verification/ Payment (D) 90 60 30 0 Interstation Distance Matrix—Improved Layout Pick Up Pick Up Verification Paperwork Advising Class of Status and Forms Station Cards and Payment (A) (B) (C) (D) Paperwork/ Forms (A) 0 30 30 60 Advising (B) 30 0 60 90 Class Cards (C) 30 60 0 30 Verification/ Payment (D) 60 90 30 0 (b) Improved layout: 9.17 Performance Time Task Must Follow Task (in minutes) This Task A 1 — B 1 A C 2 A D 1 C E 3 C F 1 C G 1 D, E, F H 2 B I 1 G, H 13 (a) Load  Distance A  B: 450  30 = 13,500 A  C: 550  30 = 16,500 A  D: 50  60 = 3,000 B  A: 350  30 = 10,500 B  C: 200  60 = 12,000 C  D: 750  30 = 22,500 78,000 (b) or Efficiency 78% with a cycle time of 3.33. Multiple layouts with this efficiency exist. (d) Idle time  1  1  2 min per cycle  60 cycles (boats)  2 min  120 min; so it’s 2 hours per day