MATH 202 Final, Spring 2005

American University of Beirut · Differential Equations · 16 pages

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MATH 202 Final, Spring 2005, page 1

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MM MTA DLO or a Sey 005 Fingal exan srlubors | ; Sechtrs \-4 CPpfesse— Kcans\ Chori - Ne) : USE FOR ANSWER < corZ 4 dg » Marte] 87 “Ly dy - Bae a \4 6°53 - = d C . Say ta = F Peg Sythe) Pee sly at ‘ ye 9) 7.uing Room Not To Be Taken Out: Reserva R- Not To Be ‘Taken Ou: Reserve Ro ae QS <a fer) alas) oo £ oral = & as loons oO rome) 35 pop pp es ee t-te ~al USE FOR ANSWER A ® Le ce upare sm g'H ond Nez sx yA aay BR Rags ep tangy org © Ee | Nx = ye + say py t ag PF + 179 Mx Weed Ty = Na Lee pA Pare z z _3ytnt Sage IPT I™ 4 ack iy)e # Cy) tne eS (7 )= x $ +z BB * 4g a eer sles og. S tes 2 (47° oho gry +a aa) Ke WCH)Ee G d Y saan became: sero (Fide 4p) MN Tyg No HTX |G Qh =t USE FOR ANSWER (3) We q" ~ ty" +4-° CRaract. Er: mintm el = ® Gu-i) = ae | mism, = 4 4 = & OC € +6, xe | a = alex, Lf Pe 2- bz ext Leads 24x Lf A=d4; -4GA+tB=°o BG |; 2) -7B+eC=0 C=8-2=6 | ~ ~ xe +uxre Hoe, 4 — x x e veschar et faust ose” ese” be greg ul ee Uy! xe~=0 1% es bere * Ue + Uy eae KOE A 1x _ e* 4 = Arckanx U;, € = pare fe! Paw fe ¢ a r f / ~ dX U is Uo = ~ hy KH u, = LH V2] xe 1 2 MM, a Qa x +1) TOI i ioe ae ie ee sa A a A SO USE FOR ANSWER _ (y) Cha ractevishi Gu. r(r-(er)- a c(c-1) (r-2) -&8 (r-1) =o Cr-1 )(r%-20-8) =0 A= 1+8=3 = a-s= 74 cod m= oe SG. z gy “Ly 3 3 4 - . neo 4 = C K+ Cy % + Cz2 =6-2Gk 44G% (> bem , +1%CgX y(4)= 4, A206, +O +03 ye ; $= C,-2Cg +UCs 4" (=o; Or cz £{(2Cz (co =-2c5 | “20, = tC 42 C, ~ C3 72 1 +865 2. USE FOR ANSWER i oe nro = P 2 . 6) a Sox" 4 = S nur” noo ce OO nee Sin(n- yar 4 Zak n= n=ro eer ees oo ee Oe ! 1 | t | {-+ 4 1 bobtt tp pl pbb FELL Efe 7 aa USE FOR ANSWER ~ Ceneral Soli him! USE FOR ANSWER nec-/ 5 = Ze (ner) % Pe Cn (nee (mere) % A USE FOR ANSWER G4) IQ Bt) Ce “—~ 4 > & & 7 1 — Ceo OL TS +) Ce = 9 USE FOR ANSWER 6 OQ w Lif 7 Lyfe ¥-sge al -s 7 -@ sjaaajee Se HH EH i] FEET ET) ee rh ELH FEREMY PRE 4: SPC EEC: USE FOR ANSWER [7 $43 SF - 553 ® °) Stusti3 SHU +4 +9 ~ Gre 5 s+z n ' 3 -— (s#e"49 3 G+z)r3 Vi Bg = ir G2) +9 t -2k 4 ¢f