EECE 310 Homework 3 Solution, Fall 2011

American University of Beirut · Electronics · 12 pages · with solution

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EECE 310 Homework 3 Solution, Fall 2011, page 1

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EECE 310 Homework 3 Solution, Fall 2011, page 2 EECE 310 Homework 3 Solution, Fall 2011, page 3 EECE 310 Homework 3 Solution, Fall 2011, page 4 EECE 310 Homework 3 Solution, Fall 2011, page 5 EECE 310 Homework 3 Solution, Fall 2011, page 6 EECE 310 Homework 3 Solution, Fall 2011, page 7 EECE 310 Homework 3 Solution, Fall 2011, page 8 EECE 310 Homework 3 Solution, Fall 2011, page 9 EECE 310 Homework 3 Solution, Fall 2011, page 10

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< 0.2 (limit of small-signal analysis for diodes) 5 5 4 4 3 3 2 2 1 1 D D C C B B A A V(D2)=-5-0.6112=-5.6112V I(D2)=6.221pA approximately 0A V(D1)=611.2 mV I(D1)=559.3uA a) 600.0mV 611.2mV 9.000V 611.2mV -5.600V -5.600V -5.000V -5.000V 0V <Doc> <RevCode> <Title> A 1 1 Sunday, October 16, 2011 Title Size Document Number Rev Date: Sheet of 0 15k 559.3uA 5 20 559.3uA 0.6 6.221pA 20 0.6 5k 6.221pA D_ideal D1 559.3uA 9 D_ideal D2 6.221pA 5 5 4 4 3 3 2 2 1 1 D D C C B B A A V(D2)=610.1-3.437=606.663mV I(D2)=333.6uA V(D1)=610.1 mV I(D1)=505.4uA b) 600.0mV 610.1mV 9.000V 610.1mV 610.1mV 3.437mV -5.000V 0V 603.4mV <Doc> <RevCode> <Title> A 1 1 Sunday, October 16, 2011 Title Size Document Number Rev Date: Sheet of 0 10k 839.0uA 5 20 505.4uA 0.6 333.6uA 20 0.6 15k 333.6uA D_ideal D1 505.4uA 9 D_ideal D2 333.6uA 5 5 4 4 3 3 2 2 1 1 D D C C B B A A V(D2)=-9-5=-14V I(D2)=14.61pA approximately 0A V(D1)=-5 V I(D1)=5.61pA approxiamtely 0A c) -600.0mV -600.0mV 5.000V 5.000V -9.600V -9.000V -9.000V 0V -9.600V <Doc> <RevCode> <Title> A 1 1 Sunday, October 16, 2011 Title Size Document Number Rev Date: Sheet of 0 10k 20.22pA 9 20 5.610pA 0.6 14.61pA 20 0.6 5.610pA 5k 14.61pA D_ideal D1 5.610pA 5 D_ideal D2 14.61pA