EECE 310 Exam, Spring 2008
American University of Beirut · Electronics · 1 page
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Test 9
(Jan 7, 2008)
Assuming is very large and VBE = 0.7 V,
determine the collector-emitter voltage and the currents in
the circuit.
Solution: VB =
V.
VE = 4 – 0.7 = 3.3 V.
IT + I =
= 1 mA.
VC = 12 = 21 = 10 V.
VCE = VC – VE = 10 – 3.3 = 6.7 V.
The BJT is in the acrive region, since VCB > 0.
I =
= 0.5 mA.
IT = 1 – 0.5 = 0.5 mA.
Current in voltage divider is
mA.
+12 V
10 k
2 k
13.4 k
3.3 k
5 k
+12 V
10 k
2 k
13.4 k
3.3 k
5 k
IT
IT
I
IT + I
IT + I
VB
VE
VC