EECE 310 Exam, Spring 2008
American University of Beirut · Electronics · 1 page
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Test 4
(October 29, 2007)
In the circuit shown, the zener
diode has VZ0 = 5 V, with
negligible rZ. In the forward
direction, VD0 = 1 V with
negligible rD. If vSRC is the
voltage waveform shown,
determine the average, or dc,
voltage vO, assuming a very
large capacitor.
Solution: During the negative half
cycle,
and the charge
gained is
. During the
positive half cycle,
and the charge lost is
.
Equating these charges gives VC = 0.4 V. The current is
A during the
positive half cycle and
A during the negative half cycle. The average
voltage vO across the resistor is
. This could have been argued
from the fact that since the net charge through the resistor is zero, the voltage across it
must be zero.
As a check, the average of vSRC is
V. Adding 0.4 to this, gives
1.4 V, which must be the average voltage across the diode and the 50 resistor. Since
the latter voltage is zero, the average voltage across the diode must be 1.4 V. The
voltage across the diode is
V, as it should be.
VC
50
_
+
_
+
+
_
1 V
5 V
VC
50
_
+
_
+
+
5 V
10 V
_
I
I
vSRC
VC
50
_
+
+
_
t, s
vSRC, V
10
-5
1
2.5
+
–
vO