EECE 460 Homework, Spring 2008

American University of Beirut · Control Systems · 2 pages

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EECE 460 Homework, Spring 2008, page 1

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EECE 460 Homework, Spring 2008, page 2

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B-5-27. From Figure 5-89(b) we have a CO K ___ oF Ro) Js*+ Kk, stK ste ks st £ By substituting K/J = 4 into this last equation, we obtain CE) _ $ R&) Ste ehyst ¢ Since Wy = 2, 5= 0.6, and 25¢/y = 4Ry, we have K= me =0.6 B-5-30. CO _ Ges) Ks+b = = RG) 1+ G(s) S*+astb (s*+astb) G6) = (ks+ est Go] or The steady-state error in the unit-ramp response is =-L.f,.— = Ls, S(Sta-k) — a-k C= = = kV see S56) Soo SC Ks+h) b