MATH 201 Chapter 16 Summary, Fall 2011
American University of Beirut · Calculus and Analytical Geometry III · 4 pages
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Chapter 16: Line Integrals
Section 1:
Definition 1:
A curve in space is a function ( )t
r
from a closed interval [
a,b]
to space by: ( )
( )
( )
( )k
j
i
l t
h t
g t
r t
+
+
=
,
b
t
a
≤
≤
.
We shall always assume that ( )
( )
( )
( )k
j
i
l t
h t
g t
r t
'
'
'
'
+
+
=
exist and is continuous everywhere in [
a,b]
.
Note:
The curve of the line segment from A to B where (
3 )
2
1
,
,
a
A a a
and (
3 )
2
1
,
,
B b b b
is
( )
(
)
[
]
(
)
[
]
(
)
[
]k
j
i
3
3
2
2
1
1
1
1
1
tb
t a
tb
t a
tb
t a
r t
+
−
+
+
−
+
+
−
=
Definition 2:
Suppose C : ( )
( )
( )
( )k
j
i
l t
h t
g t
r t
+
+
=
with
b
t
a
≤
≤
.
Given (
f x y z)
, ,
a function of 3 variables which is continuous on C. The line integral of f over C is defined as
(
)
(
)
∫
∑
=
∆ →
∆
=
C
n
m
m
m
m
m
S
S
z
y
f x
x y z dS
f
1
0
,
,
lim
, ,
where (
)
(
m )
m
m
z
y
x
z
y
x
,
,
,.........,
,
,
0
0
0
are successive points on C,
∆Sm
is the length of C between (
)
(
)
,
,
and
,
,
1
1
1
m
m
m
m
m
m
z
y
x
z
y
x
−
−
−
, and
(
Sn )
S
S
∆
∆
=
∆
,....,
max
1
.
Formula for evaluating line integral:
Suppose C and f are as above: Then:
(
)
( ( ) ( ) ( )
) ( )
∫
∫
=
b
a
C
f g t h t l t v t dt
f x y z dS
,
,
, ,
Where: ( )
r ( )t
v t
= '
.
Note:
( )
( )
( )
( )k
j
i
l t
h t
g t
r t
C
+
+
=
1 : 1
is a curve in space. (
b
t
a
≤
≤
).
2
C is a curve in space with the same path (as
1
C ) but in opposite direction. Then
( )
(
)t
b
r a
r t
−
+
=
1
2
Section 2:
Definition 1:0
A vector field on an open region D in space is a function
(
)z
F x y
, ,
from D to space given by
(
)
(
)
(
)
(
)k
j
i
P x y z
N x y z
M x y z
F x y z
, ,
, ,
, ,
, ,
+
+
=
.
We shall always assume that M, N, and P have continuous first order partial derivatives.
Note:
If
(
f x y z)
, ,
is a function of three variables with continuous first and second order partial derivatives, then
k
j
i
z
y
x
f
f
f
f
+
+
∇ =
is a vector field on the interior of Domain f.
Definition 2:
Suppose D is an open region in space.
Suppose
k
j
i
P
N
M
F
+
+
=
is a vector field on D.
Suppose
( )
( )
( )
( )k
j
i
l t
h t
g t
C r t
+
+
=
:
(
b
t
a
≤
≤
) is a curve in D.
The unit tangent vector to C is defined as
( )
v( )t
T = v t
provided ( )
v t ≠ 0
.
The line integral of F over C is defined as ∫
C
F.TdS
.
If F represents a force, then above integral is called the work integral. In this case, we write work = work done
by F over C = ∫
C
F.TdS
.
If F represents a velocity field, then above integral is called a flow integral. In this case, we write flow = flow of
F along C = ∫
C
F.TdS
.
If F represents a velocity field and C is closed
( )
( )
(
r b )
r a
=
i.e.
, then above integral is called a circulation
integral. In this case, we write circulation = circulation of F around C = ∫
C
F.TdS
.
Formula for evaluating line integrals of vector field.
Suppose F and C are as above. Then:
∫
∫
=
b
a
C
dt dt
F dr
F TdS
.
.
Notation:
Suppose
k
j
i
P
N
M
F
+
+
=
is a vector field on some open region D in space.
Suppose
( )
( )
( )
( )k
j
i
l t
h t
g t
C r t
+
+
=
:
with
b
t
a
≤
≤
is a curve in D, then
∫
∫
+
+
=
C
C
Pdz
Ndy
Mdx
F.TdS
Section 3:
Definition 1:
Suppose
k
j
i
P
N
M
F
+
+
=
is a vector field on an open region D in space.
(
)z
f x y
, ,
is a function of three variables which is differentiable everywhere in D.
If
(
)
(
)z
F x y
f x y z
, ,
, ,
=
∇
for all points (
)z
x y
, ,
in D, we say that f is a potential function for F on D.
Definition 2:
Suppose F is a vector field on an open region D in space. We say that F is conservative if the line integral of F
is path independent in D. i.e., if A and B are two points in D and
2
1
C and C
are two curves in D joining A to B,
then
∫
∫
=
2
1
.
.
C
C
F TdS
F TdS
.
Theorem 1: Fundamental theorem of line integral (FTLI):
Suppose
k
j
i
P
N
M
F
+
+
=
is a vector field on an open and connected region in space.
Then: F is conservative on D ⇔ F has a potential function F on D.
In this case
( )
( )
f A
f B
TdS
F
C
−
=
∫
.
for every curve C in D joining A to B.
Definition 3:
A region D in space is connected if any two points in D can be joined by a curve which lies entirely in D.
Definition 4:
A region D in space is simply connected if any closed curve in D can be contracted to a point without ever
leaving D.
Theorem 2: The Curl Test:
Suppose
k
j
i
P
N
M
F
+
+
=
is a vector field on an open connected, simply connected region D in space.
Then: F is conservative on D ⇔
0
Curl
F =
Where
P
N
M
z
y
x
F
F
∂
∂
∂
∂
∂
= ∂
∇ ×
=
k
j
i
Curl
Definition 5:
Suppose D is an open region in space.
A differential form on D is an expression of the form
(
)
(
)
(
P x y z)dz
N x y z dy
M x y z dx
, ,
, ,
, ,
+
+
.
We shall always assume that M, N, and P have continuous first order partial derivatives.
Definition 6:
(
)z
f x y
, ,
is a function of three variables with continuous first and second order partial derivatives. Then the
differential of f is the differential form
f dz
f dy
dx
f
z
y
x
+
+
.
Definition 7:
Suppose D is an open and connected region in space.
Suppose
Pdz
Ndy
Mdx
+
+
is a differential form on D.
Then: If there is a function (
f x y z)
, ,
such that
Pdz
Ndy
Mdx
df
+
+
=
we say that the given differential form is
exact
k
j
i
P
N
M
+
+
⇔
is conservative.
Section 4:
Definition 1:
(
)
(
)
(
)j
i
N x y
M x y
F x y
,
,
,
+
=
is a vector field on an open region R in the plan.
Then, the divergence of F is defined as:
(
)
y
N
x
M
N
M
y
x
F
F
∂
+ ∂
∂
= ∂
+
∂
+ ∂
∂
∂
=
= ∇
j
i
j
i
.
.
div
Note:
If
(
)
(
)
(
)j
i
N x y
M x y
F x y
,
,
,
+
=
, then
k
j
i
k
j
i
∂
− ∂
∂
+ ∂
∂
+ ∂
∂
= − ∂
∂
∂
∂
∂
∂
= ∂
= ∇ ×
y
M
x
N
z
M
z
N
P
N
M
z
y
x
F
Curl F
So the k component of Curl F is (
)
y
M
x
N
F
∂
− ∂
∂
= ∂
k.
Curl
.
Theorem 1:
a. Green’s Theorem: Flux Divergence form:
Suppose
j
i
N
M
F
+
=
is a vector field in the plane.
Suppose C is a simple closed curve in the plane .Simple means, the position vector of the curve is one to one on
(
a,b)
.
Then: flux of F across C = ∫∫
R
div FdA
.
This can be written as
∫∫
∫
∂
+ ∂
∂
∂
=
−
R
C
y dxdy
N
x
M
Ndx
Mdy
b. Green’s Theorem: Circulation Curl form:
Suppose F, C and R are as above. Then:
Counterclockwise circulation of F around C =
(
)
(
)
∫∫
R
dA
Curl F k.
This can be written as:
∫∫
∫
∂
− ∂
∂
∂
=
+
R
C
dxdy
y
M
x
N
Ndy
Mdx